a) P(heads, then P)b) P(tails, then a vowel)2. A coin is tossed, then aletter from the wordINDIANAPOLIS is selected atrandom. Find eachprobability.c) P(tails, then N)d) P(heads, then D or I)

Respuesta :

c.)

When a coin is tossed, there is a probability of 1/2 getting a tail.

The word INDIANAPOLIS has 12 letters in total, with 2 Ns. This gives us a probability of 2/12.

Therefore:

[tex]P\left(tails,thenN\right)=\frac{1}{2}\times\frac{2}{12}=\frac{1}{12}[/tex]

d.) P(heads, then D or I)

When a coin is tossed, there is a probability of 1/2 getting a heads).

There would be a probability of 5/12 when getting a D or an I.

Therefore:

[tex]P=\frac{1}{2}\times\frac{5}{12}=\frac{5}{24}[/tex]