Explanation:
a) We have to find the number of moles of oxygen gas that are present in 22 g of it. To convert from grams to moles we usually use the molar mass. To find the molar mass of oxygen gas we need the atomic mass of O.
atomic mass of O = 16.00 amu
molar mass of O = 16.00 g/mol
molar mass of Oâ‚‚ = 2 * 16.00 g/mol
molar mass of Oâ‚‚ = 32.00 g/mol
moles of Oâ‚‚ = 22 g * 1 mol/(32.00 g)
moles of Oâ‚‚ = 0.6875 moles = 0.7 moles
b) 2 COâ‚‚ --> 2 CO + Oâ‚‚
According to the coefficients of the reaction 2 moles of COâ‚‚ will produce 2 moles of CO and 1 mol of Oâ‚‚. Then the molar ratio between COâ‚‚ and Oâ‚‚ is 2:1. We will use that ratio to find the number of moles of COâ‚‚ that are required to produce 0.7 moles of Oâ‚‚.
2 moles of COâ‚‚ : 1 mol of Oâ‚‚
moles of COâ‚‚ = 0.7 moles of Oâ‚‚ * 2 moles of COâ‚‚/(1 mol of Oâ‚‚)
moles of COâ‚‚ = 1.4 moles
Answer:
a) Percy has to produce 0.7 moles of oxygen gas.
b) 1.4 moles of carbon dioxide are required.