We were given that:
[tex]f\mleft(x\mright)=2\mleft(x\mright)^2+5\sqrt[]{\mleft(x+2\mright)}[/tex]
We will proceed to solve for when: x = 0. We have:
[tex]\begin{gathered} f(0)=2(0)^2+5\sqrt[]{(0+2)} \\ f(0)=0+5\sqrt[]{2} \\ f(0)=5\sqrt[]{2} \\ f(0)=7.0711\approx7.07 \\ f(0)=7.07 \\ \\ \therefore f(0)=7.07 \end{gathered}[/tex]
