Given the sequence:
7, -14, 28, -56,
To find the 7th term of the geometric sequence, use the formula below:
[tex]a_n=ar^{(n-1)}[/tex]where,
a is the first term = 7
n is the number of terms = 7
r = common ratio =
[tex]r\text{ = }\frac{\sec ond\text{ term}}{\text{first term}}\text{ = }\frac{-14}{7}=\text{ -2}[/tex]Thus, we have:
[tex]\begin{gathered} a_7=\text{ 7(}-2^{(7-1)}) \\ \\ \text{ = 7 }(-2^6) \\ \\ \text{ = }7(-64) \\ \\ \text{ = }-448 \end{gathered}[/tex]The 7th term is -448
ANSWER:
A) -448
