The point (6, -3) is on the graph of y = f(x).
To determine the corresponding point on the following transformations of f.
[tex]y=\frac{1}{2}f(x+3)[/tex]
At (6, -3) ,
[tex]y=\frac{1}{2}f(6+3)=\frac{1}{2}f(9)[/tex][tex]-3=\frac{1}{2}f(9)[/tex][tex]f(9)=-6[/tex]
Hence the corresponding point is obtained as
[tex](9,-6)[/tex]
