In order to solve this equation for x, let's do the following steps:
[tex]\begin{gathered} (2x-1)^2=9 \\ 2x-1=\sqrt[]{9} \\ 2x-1=\pm3 \\ \begin{cases}2x-1=3\to2x=4\to x=2 \\ 2x-1=-3\to2x=-2\to x=-1\end{cases} \end{gathered}[/tex]So the solutions of this equation are x = 2 and x = -1, therefore the correct option is B.
