Exercise is for a right triangle, then we can use triconometric ratios, on this case we will use sine
[tex]\sin (\alpha)=\frac{O}{H}[/tex]
where alpha is the reference angle, O the opposite side to the reference angle and H the hypotenuse of the triangle
then using 37° as reference angle we replace
[tex]\sin (37)=\frac{x}{15}[/tex]
and solve for x
[tex]\begin{gathered} 15\sin (37)=x \\ x=9.027 \end{gathered}[/tex]
the rounded value of x is 9, then right option is C
