Answer:
c.32
Explanation:
Hello,
In this case, it is possible to determine it by building the subshells organization for the first four shells as shown below:
[tex]1s^2\\2s^2\ 2p^6\\3s^2\ 3p^6\ 3d^{10}\\4s^2\ 4p^6\ 4d^{10}\ 4f^{14}[/tex]
In such a way, counting the electrons at the n=4 shell, the result is 32 (2+6+10+14), so the answer is c.
Best regards.
