Respuesta :

hrrs01
You can use the following sentence:

[tex]x_1,_2 = \frac{-b+- \sqrt{b^2-4ac} ) }{2a} [/tex]

or if youre on a phone:
x_1,_2 = (-b+/-sqrt(b^2-4ac))/2a
where 6 is a, -8 is b, and 30 is c

in phone formatting:

x=(-(-8) +/- sqrt((-8)^2-4*6*-30))/2*6x=(8 +/- sqrt(64+720))/12
x=(8 +/- 28)/12

x_1= 36/12 = 3
x_2 = -20/12 = -5/3

Or on pc: 
[tex]x_1= \frac{36}{12} = 3 x_2 = -\frac{20}{12} = - \frac{5}{3} [/tex]

Answer is 2(3a + 5)(a - 3)

hope this helps! :)

Q&A Education