Respuesta :
To solve for the concentration of nitric acid in mol/L or also M. We use the equation,
M₁V₁ = M₂V₂
Where M stands for the molarity and V is for volume. Substituting the known values,
(0.10 M)(13.0 mL) = (M₂)(17 mL)
M₂ = 0.076 M
Thus, the concentration of the nitric acid is approximately 0.076 M.
M₁V₁ = M₂V₂
Where M stands for the molarity and V is for volume. Substituting the known values,
(0.10 M)(13.0 mL) = (M₂)(17 mL)
M₂ = 0.076 M
Thus, the concentration of the nitric acid is approximately 0.076 M.
The concentration of [tex]{\text{Ba}}{\left( {{\text{OH}}} \right)_2}[/tex]solution is [tex]\boxed{{\text{0}}{\text{.076 M}}}[/tex]
Further Explanation:
The concentration is the proportion of substance in the mixture. The most commonly used concentration terms are as follows:
1. Molarity (M)
2. Molality (m)
3. Mole fraction (X)
4. Parts per million (ppm)
5. Mass percent ((w/w) %)
6. Volume percent ((v/v) %)
Molarity is a concentration term that is defined as the number of moles of solute dissolved in one litre of the solution. It is denoted by M and its unit is mol/L.
The molarity equation is given by the following expression:
[tex]{{\text{M}}_{\text{1}}}{{\text{V}}_{\text{1}}} = {{\text{M}}_{\text{2}}}{{\text{V}}_{\text{2}}}[/tex]
Here,
[tex]{{\text{M}}_{\text{1}}}[/tex] is the molarity of the first solution.
[tex]{{\text{V}}_{\text{1}}}[/tex] is the volume of the first solution.
[tex]{{\text{M}}_{\text{2}}}[/tex] is the molarity of the second solution.
[tex]{{\text{V}}_{_{\text{2}}}}[/tex] is the volume of the second solution.
In the concerned question, [tex]{\text{Ba}}{\left( {{\text{OH}}} \right)_2}[/tex]is neutralized by [tex]{\text{HN}}{{\text{O}}_{\text{3}}}[/tex]. So molarity equation becomes,
[tex]{{\text{M}}_{{\text{Ba}}{{\left( {{\text{OH}}} \right)}_2}}}{{\text{V}}_{{\text{Ba}}{{\left( {{\text{OH}}} \right)}_2}}} = {{\text{M}}_{{\text{HN}}{{\text{O}}_{\text{3}}}}}{{\text{V}}_{{\text{HN}}{{\text{O}}_{\text{3}}}}}[/tex] …… (1)
Here,
[tex]{{\text{M}}_{{\text{Ba}}{{\left( {{\text{OH}}} \right)}_2}}}[/tex] is the molarity of [tex]{\text{Ba}}{\left( {{\text{OH}}} \right)_2}[/tex] solution.
[tex]{{\text{V}}_{{\text{Ba}}{{\left( {{\text{OH}}} \right)}_2}}}[/tex]is the volume of [tex]{\text{Ba}}{\left( {{\text{OH}}} \right)_2}[/tex]solution.
[tex]{{\text{M}}_{{\text{HN}}{{\text{O}}_{\text{3}}}}}[/tex] is the molarity of [tex]{\text{HN}}{{\text{O}}_{\text{3}}}[/tex]solution.
[tex]{{\text{V}}_{{\text{HN}}{{\text{O}}_{\text{3}}}}}[/tex] is the volume of [tex]{\text{HN}}{{\text{O}}_{\text{3}}}[/tex]solution.
Rearrange equation (1) to calculate [tex]{{\text{M}}_{{\text{HN}}{{\text{O}}_{\text{3}}}}}[/tex].
[tex]{{\text{M}}_{{\text{HN}}{{\text{O}}_{\text{3}}}}} = \frac{{{{\text{M}}_{{\text{Ba}}{{\left( {{\text{OH}}} \right)}_2}}}{{\text{V}}_{{\text{Ba}}{{\left( {{\text{OH}}} \right)}_2}}}}}{{{{\text{V}}_{{\text{HN}}{{\text{O}}_{\text{3}}}}}}}[/tex] …… (2)
The value of [tex]{{\text{V}}_{{\text{Ba}}{{\left( {{\text{OH}}} \right)}_2}}}[/tex] is 13 mL.
The value of [tex]{{\text{M}}_{{\text{Ba}}{{\left( {{\text{OH}}} \right)}_2}}}[/tex] is 0.100 M.
The value of [tex]{{\text{V}}_{{\text{HN}}{{\text{O}}_{\text{3}}}}}[/tex] is 17 mL.
Substitute these values in equation (2).
[tex]\begin{aligned}{{\text{M}}_{{\text{HN}}{{\text{O}}_{\text{3}}}}}&=\frac{{\left( {{\text{0}}{\text{.100 M}}} \right)\left( {{\text{13 mL}}} \right)}}{{\left( {{\text{17 mL}}}\right)}}\\&=0.{\text{07647 M}}\\&\approx {\text{0}}{\text{.076 M}}\\\end{aligned}[/tex]
Hence the concentration of barium hydroxide solution is 0.076 M.
Learn more:
1. What is the mass of 1 mole of viruses: https://brainly.com/question/8353774
2. Determine the moles of water produced: https://brainly.com/question/1405182
Answer details:
Grade: Senior School
Subject: Chemistry
Chapter: Concentration terms
Keywords: molarity, 13 mL, 17 mL, 0.076 M, Ba(OH)2, M1, V1, M2, V2, HNO3, 0.100 M, molarity, volume.
