Respuesta :
Its A. 16(pie)x^2+80(pie)x +100(pie) because,S=4(pie)r^2 for the surface area of a sphere.
V=hpr^2 (for a cylinder) we are given r=(2x+3) and h=(6x+1) so
V=p(6x+1)(2x+3)^2
V=p(6x+1)(4x^2+12x+9)
V=p(24x^3+72x^2+54x+4x^2+12x+9)
V=p(24x^3+76x^2+66x+9) so B.
...
A=4pr^2 and r=(2x+5) so
A=4p(4x^2+20x+25)
A=p(16x^2+80x+100) so A.
V=p(6x+1)(2x+3)^2
V=p(6x+1)(4x^2+12x+9)
V=p(24x^3+72x^2+54x+4x^2+12x+9)
V=p(24x^3+76x^2+66x+9) so B.
...
A=4pr^2 and r=(2x+5) so
A=4p(4x^2+20x+25)
A=p(16x^2+80x+100) so A.