Respuesta :
The atoms combine with other atoms in order to complete their octet (eight electrons in their valence shell, noble gas configurations) and attain stability. The combination of atoms with other atoms to form molecule takes place by either sharing of electrons or by transfer of electrons from one atom to other atom.
Fluorine, [tex]F[/tex] and bromine, [tex]Br[/tex] are in the same group on the periodic table that is halogen group (Group 17). The halogen group has electronic configuration as [tex]ns^{2}np^{5}[/tex] that means they are deficient of one electron to complete their octet and attain stability. So, they gain 1 electron and result in the formation of anion and form compounds by transfer of electrons.
Hence, both a fluorine atom and a bromine atom gain one electron, and both atoms become stable.
To form a bond, both fluorine and bromine atoms lose one electron and become stable. So the correct option is A.
What kind of bond is formed by fluorine and bromine?
The two atoms combine with each other atoms to complete their valence shell. There must be eight electrons in the valence shell of all atoms to form an octet. This makes them reach the configuration of their nearest noble gas. When an atom completes an octet, it reaches a stable confirmation.
This combination can happen by sharing of electrons. To do that, electrons are transferred from one atom to another. This mutual sharing of electrons results in the formation of a covalent bond.
The atoms Fluorine, F and Bromine, Br are present in the same group of the periodic table, group 17. This is called the halogen group. the atoms of elements of the halogen group need only one electron to complete the octet in their valence shells. And by that, they can reach the configuration of their nearest noble gas. So, during bond formation, both of them share one electron each which results in the formation of a single covalent bond
Therefore, the correct option is A.
Read more about covalent bonds, here
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