ersudra
ersudra
05-05-2017
Mathematics
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How do you solve a(3x-8)=b-18x
Respuesta :
Newtion
Newtion
05-05-2017
[tex]\displaystyle a(3x-8)=b-18x\\\\3ax-8a=b-18x\\\\3ax+18x=b+8a\\\\3x(a+6)=b+8a\\\\3x= \frac{b+8a}{a+6}\quad, a\ne-6\\\\x= \frac{b+8a}{3(a+6)} [/tex]
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