blcollett blcollett
  • 05-05-2017
  • Mathematics
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5 consecutive integers of 265

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irspow
irspow irspow
  • 05-05-2017
n+n+1+n+2+n+3+n+4=265

5n+10=265

5n=255

n=51

So the integers are:

51,52,53,54, and 55
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