Respuesta :
v=u+at
v = 16.5 + (2.75)*(9) where v is the final speed
u is the initial speed
a is the acceleration
t is the time
v=41.25 m/s
v = 16.5 + (2.75)*(9) where v is the final speed
u is the initial speed
a is the acceleration
t is the time
v=41.25 m/s
Answer:
Final speed, v = 41.25 m/s
Explanation:
It is given that,
Acceleration of the bus, [tex]a=2.75\ m/s^2[/tex]
Initial velocity of the bus, u = 16.5 m/s
We have to find the velocity (v) of the bus after 9 seconds.
The rate of change of velocity is called as the acceleration of the bus. Mathematically, it can be written as :
[tex]a=\dfrac{v-u}{t}[/tex]
[tex]v=u+at[/tex]
[tex]v=16.5+2.75\times 9[/tex]
v = 41.25 m/s
So, the final speed of the bus after 9 seconds is 41.25 m/s
