Respuesta :

LammettHash
Since [tex]\cos\dfrac{3\pi}2=0[/tex], and [tex]\cos t<0[/tex] for [tex]\pi<t<\dfrac{3\pi}2[/tex] and [tex]\cos t>0[/tex], it follows that

[tex]\displaystyle\lim_{t\to\frac32^-}\sec\pi t=-\infty[/tex]

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