faraz90ahmad
faraz90ahmad
05-07-2017
Mathematics
contestada
Find the zero of f(x) = x^5-12x^2+32x
Respuesta :
mathmate
mathmate
19-07-2017
The zeroes of
f(x) = x^5-12x^2+32x can be found by factoring,
f(x) = x^5-12x^2+32x=(x-8)(x-4)
By the zero product theorem, (x-8)=0 or (x-4)=0 which means
x=8 or x=4.
So the zeroes of f(x) are S={4,8}
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