Find the volume of a frustum of a right pyramid whose lower base is a square with a side 5in. And whose upper base is a square with a side 3in., and whose altitude is 12 in. Round your answer to the nearest hole number.
A- 196 cu in.
B- 47 cu in.
C- 1038 cu in.
D- 226 cu in.

Respuesta :

The volume of the frustrum is the difference in the volumes of these two pyramids: 
30 * 5^2 / 3 - 18 * 3^2 / 3 
= 750/3 - 162/3 
= 250 - 54 
= 196 cubic inches.

You're Answer is A- 196 cu in.