Respuesta :

irspow
Upon slight rearranging:

5xy-15y-40x+120, now factor 1st and 2nd pair of terms

5y(x-3)-40(x-3) which is equal to:

(5y-40)(x-3)  if we factor the first parenthetical term as well

5(y-8)(x-3)

So (y-8) is a factor

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