Given:
p* = 0.35, the populatin proportion.
Sp = 0.05, the margin of error
Let n = the size of the sample.
Because the standard error is 0.05, therefore
[tex] \sqrt{ \frac{p(1-p)}{n} } =0.05[/tex]
[tex] \sqrt{ \frac{0.35(1-0.35)}{n} } =0.05[/tex]
[tex] \frac{0.2275}{n} =0.05^{2} =0.0025[/tex]
n = 0.2275/0.0025 = 91
Answer: The sample size is 91.
