Respuesta :

Bqre

Answer:

[tex](f + g)(-1) = 0[/tex]

Step-by-step explanation:

[tex]f(x) = 4 + 2x\\g(x) = x^2 - 3\\\\(f + g)(x) = f(x) + g(x) = 4 + 2x + x^2 - 3 = x^2 + 2x + 1\\\to (f + g)(x) = (x + 1)^2\\\\(f + g)(-1) = (-1 + 1)^2 = 0^2 = 0[/tex]