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A 230.0 kg bear grasping a vertical tree slides down at constant velocity. What is the friction force between the tree and the bear?

Respuesta :

Well, it's equal to the weight of the bear, which is 230*10=2300 N
UnicornFudge
Hi there! Thanks for asking here on Brainly. ✉

Solving the dynamic equilibrium: 

Friction = Gravity = ma
(230.0 kg)*(10 m/s2) =
23000 N

So the friction force between the tree and bear is 2300 N.

Hope that helps! ★ If you have further questions about this question or need more help, feel free to comment below or leave me a PM. -UnicornFudge aka Nadia

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