so, to get the inverse relation of anything, as you'd already know, we first do a quick switcharoo on the variables, and then solve for "y".
[tex]\bf \stackrel{f(x)}{y}=-\cfrac{3}{-x-3}-2\qquad inverse\implies \boxed{x}=-\cfrac{3}{-\boxed{y}-3}-2
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x+2=\cfrac{3}{-(-y-3)}\implies x+2=\cfrac{3}{y+3}\implies (x+2)(y+3)=3
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xy+3x+2y+6=3\implies xy+2y=3-3x-6
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y(x+2)=-3x-3\implies y=\cfrac{-3x-3}{x+2}\implies \stackrel{f^{-1}(x)}{y}=\cfrac{-3(x+1)}{x+2}[/tex]
