Given the table below which contains data from 200 endothemic reactions involving sodium bicarbonate:
[tex]\begin{tabular}
{|c|c|}
Final Temperature Conditions&Number of Reactions\\[1ex]
266 K&48\\
271 K&60\\
274 K&92
\end{tabular}[/tex]
We find the probability distribution function as follows:
Let X denote the final temperature, then
[tex]P(X = 266) = \frac{48}{200} =0.24\\ \\ P(X = 271) = \frac{60}{200} =0.3\\ \\ P(X = 274) = \frac{92}{200} =0.46[/tex]
