Answer: The factorized form of [tex]n^2-25[/tex] will be
[tex](n-5)(n+5)[/tex]
Explanation:
Since we have given that
[tex]n^2-25[/tex]
Now, we need to factorize the expression,
We know the formula for "difference of squares" which is given by
[tex]a^2-b^2=(a+b)(a-b)[/tex]
Using the formula, we get
[tex]n^2-25=n^2-5^2=(n-5)(n+5)[/tex]
Hence, the factorized form of [tex]n^2-25[/tex] will be
[tex](n-5)(n+5)[/tex]
