Respuesta :
I would assume air resistance is negligible and so the acceleration of the package would be approximately 9.81 m/s².
Taking downwards as positive, use v²=u²+2as.
v²=(-2)²+2(9.81)(14)
v=16.7 m/s
Taking downwards as positive, use v²=u²+2as.
v²=(-2)²+2(9.81)(14)
v=16.7 m/s
The velocity of the package just before it hits the ground is 16.7 m/s.
What is velocity?
The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.
Initial velocity(u)=2 m/s
V(velocity of hitting)=?
S(distance travelled)= 14 meters
The velocity of the package just before it hits the ground is found as;
From the Newton's third equation of motion;
v²=u²+2as.
v²=(-2)²+2(9.81)(14)
v=16.7 m/s
Hence,the velocity of the package just before it hits the ground is 16.7 m/s.
To learn more about the velocity, refer to the link;
https://brainly.com/question/862972
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