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Solve the linear-quadratic system algebraically.
y = x^2 + 2x + 9
y − 9 = x

Respuesta :

y - 9 = x
Add both sides by 9
y = x+9

Substitute y = x+9 into the other equation
y = x^2 + 2x + 9
x+9 = x^2 + 2x + 9
Subtract both sides by 9
x = x^2 + 2x
Subtract both sides by x
0 = x^2 + 2x
If you graph this, the solutions are

 x = -1
 and
 x = 0

Plug these values into y = x+9 and you get
y = -8
and
y = 9

Your solutions are (-1, -8) and (0, 9)

Those should be your answers. Have an awesome day! :D

From your friendly Helper-in-Training, Collinjun0827
Q&A Education