What is the boiling point of water at an elevation of 1.55×104 ft ?

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04-12-2017
Chemistry

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What is the boiling point of water at an elevation of 1.55×104 ft ?

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shinmin shinmin · Answer 1 · 2017-12-13T15:44:31+01:00

shinmin shinmin

13-12-2017

The computation for this problem is:
(1.55x10^4 / 1.0x10^3) x 19.8 mm Hg
= 15.5 x 19.88 mm Hg
= 308.14 mm Hg decrease
= 308.14 x 0.05 C = 15.407 deg C
deduct this amount to 100
100 – 15.407 = 84.593 C
ANSWER: 85 deg C (rounded to 2 significant figures)

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