Given: ΔABC with Prove: Statement Reason 1. given 2. Addition Property of Equality 3. using common denominators 4. AB = AD + DB CB = CE + EB segment addition 5. Substitution Property of Equality 6. ∠ABC ≅ ∠DBE Reflexive Property of Congruence 7. ΔABC ~ ΔDBE SAS similarity criterion 8. Corresponding angles of similar triangles are congruent. 9. If the corresponding angles formed by two lines cut by a transversal are congruent, then the lines are parallel. Question 19 of 44 What is the missing step in this proof? ∠BAC ≅ ∠ACB ∠BDE ≅ ∠DEB ∠ADE ≅ ∠DEC ∠BAC ≅ ∠BDE ∠ABC ≅ ∠DBE NextReset

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Answer:

lizrios1 is, in fact, correct.

Step-by-step explanation:

i took the test and the answer is AD DB + 1=CE EB+1 and addition property of equality

In the proof of Additive property equality in triangle, the missing step is

∠BAC ≅ ∠ACB

What is Additive property?

If two expressions are "equal to each other, and we can add same value on both sides of the equations and the equation will remain equal".

According to the question,

Statement: Additive property of equality in ΔABC

Proof: Using common denominators

AB = AD + DB      [Segment Addition]

CB= CE + EB        [Segment  Addition]

substitution property of equality

∠ABC = ∠DBE [Reflexive property of Congruence]

ΔABC ≅ ΔDBE [SAS similarity criterion]

∠BAC ≅ ∠ACB corresponding angles of similar triangles are congruent.

If the corresponding angles formed by two lines cut by a transversal are congruent, then the lines are parallel.

Hence, Addition property of triangle equality is proved.

Learn more about Property of triangle here

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