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A circuit contains 3 resistors connected in series the value of R1 is 150 ohms the value of R2 is 60 ohms and the value of R3 is 620 ohms what is the total resistance in the circuit

Respuesta :

Resistances in series add algebraically.

Therefore the total resistance of R₁=150 Ω, R₂=60 Ω, and R₃=620 Ω is
R = R₁ + R₂ + R₃ = 150+60+620 = 830 Ω

Answer: 830 Ω

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