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Which quadratic equation is equivalent to (x2 – 1)2 – 11(x2 – 1) + 24 = 0? u2 – 11u + 24 = 0 where u = (x2 – 1) (u2)2 – 11(u2) + 24 where u = (x2 – 1) u2 + 1 – 11u + 24 = 0 where u = (x2 – 1) (u2 – 1)2 – 11(u2 – 1) + 24 where u = (x2 – 1)

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Respuesta :

u2 – 11u + 24 = 0 where u = (x2 – 1) the first awnser, a.
calculista

we have

[tex](x^{2}-1)^{2}-11(x^{2}-1)+24=0[/tex] --------> equation

Let

[tex]u=x^{2}-1[/tex]

substitute the value of u in the equation

[tex](u)^{2}-11(u)+24=0[/tex]

[tex]u^{2}-11u+24=0[/tex]

therefore

the answer is the first option

[tex]u^{2}-11u+24=0[/tex]  where  [tex]u=x^{2}-1[/tex]

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