Here you have two complex numbers. Multiplying these numbers remember that
[tex]i^2=-1.[/tex]
Now
[tex](4i + 3)(5 - 2i)=4i\cdot 5-4i\cdot 2i+3\cdot 5-3\cdot 2i=20i-8i^2+15-6i=\\ \\20i-8\cdot (-1)+15-6i=20i+8+15-6i=(8+15)+(20i-6i)=23+14i.[/tex]
Answer: 23+14i.
