bricynb
bricynb
06-01-2016
Chemistry
contestada
How many moles are there in 359g of NANO3?
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Willchemistry
Willchemistry
11-01-2016
Molar mass NaNO3 ( Sodium nitrate )
NaNO3 = 23 + 14 + 16*3 = 85 g/moles
1 mole NaNO3 ------------- 85 g
x moles NaNO3 ------------ 359 g
x = 359 / 85
x = 4,22 moles of NaNO3
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