Respuesta :

eugeniacarvalhp5176g
P(x)=3x^3+6x^2+5x+10
dividers of 10: {1,2,5,10}
P(-2)=3×(-2)³+6×(-2)²+5×(-2)+10=0
using the ruffini rule:
Q(x)=x+2
R(x)=3x²+5
3x²+5 = 0   impossible equation
P(X)=(x+2)(3x²+5)

Answer:

(c) Factor by Grouping