Respuesta :

konrad509

[tex] |\Omega|=52\\
|A|=\underbrace{13}_{\text{clubs}}+\underbrace{4}_{\text{jacks}}-\underbrace{1}_{\text{jack of clubs}}=16\\\\
P(A)=\dfrac{16}{52}=\dfrac{4}{13}\approx31\% [/tex]

kennethrodriguez0

Answer:

A. 4/13

Step-by-step explanation:

4/13 in percent is 30%(30.7692308 percent)

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