kkent61
kkent61
05-03-2018
Mathematics
contestada
factor 2g^3-g^2-8g+4
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yumaawesome03
yumaawesome03
05-03-2018
the answer is (2g-1) (g+2) (g-2)
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Astute
Astute
05-03-2018
Hello there!
[tex](First \ step) \\ \\ rearrange \ expression \ ((2g^3 - g^2) - 8^g) + 4) \\ \\ \boxed{\boxed{we \ know \ that \ this \ is \ not \ a \ perfect \ cube}} \\ \\We \ then \ factor... \\ \\ (g + 2) * (g - 2) \\ \\\ (final \ answer)... \\ \\\ (g + 2) * (g - 2) * (2g - 1) [/tex]
I hope this helps you!
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