Respuesta :
The explicit rule for the sequence is [tex] a_{n}=14-9n [/tex]
Let us put n=1, we get
[tex] a_{1}=14-(9 \times 1)=5 [/tex]
Now let n=2,
[tex] a_{2}=14-(9 \times 2)=-4 [/tex]
Let n=3,
[tex] a_{3}=14-(9 \times 3)=-13 [/tex]
Similarly, in this manner we obtain a sequence as
5, -4, -13, -22,.....
Since we can clearly observe that the first term is '5' and common difference is '-9'.
So, we get recursive rule for the sequence as:
[tex] a_{n}=a_{n-1}-9 [/tex] , where [tex] a_{1}=5 [/tex].
