From the second equation: y=(10-4x)/3
Substitute y to the first equation:
5x+2[(10-4x)/3] = 24
5x+[(20/3)-(8x/3)]=24
5x-(8x/3)=24-(20/3)
(15x-8x)/3=17.333
7x=17.333(3)
x=7.428
Using the second equation to find value of y:
y=(10-4x)/3; Substitute the value of x=7.428
y=[10-4(7.428)]/3
y= -6.571 (negative 6.571)
