Respuesta :

[tex]\bf z^4-65z^2+64=0\implies (z^2)^2-65(z^2)+64=0 \\\\\\ (z^2-64)(z^2-1)=0\implies \begin{cases} z^2-64=0\\ z^2=64\\ z=\pm\sqrt{64}\\ z=\pm 8\\ ------\\ z^2-1=0\\ z^2=1\\ z=\pm\sqrt{1}\\ z=\pm 1 \end{cases}[/tex]

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