The electric force F exerted on a charged particle of charge q by an electric field of intensity E is given by:
[tex]F=qE[/tex]
in our problem, the force is [tex]1.5 \cdot 10^{-3} N[/tex], while the magnitude of the charge is [tex]q=2.40 \cdot 10^{-8} C[/tex], so we can use these data and the previous formula to find the intensity of the electric field E:
[tex]E= \frac{F}{q} = \frac{1.50 \cdot 10^{-3} N}{2.40 \cdot 10^{-8 } C}=62500 N/C [/tex]
