PrettyBoyKitten
contestada

A doghouse is to be built in the shape of a right trapezoid, as shown below. What is the area of the doghouse?

A right trapezoid with top side 7 feet and height 7 feet. The bottom side is extended to the right with 5 more feet.

A doghouse is to be built in the shape of a right trapezoid as shown below What is the area of the doghouse A right trapezoid with top side 7 feet and height 7 class=

Respuesta :

First we will find the total measure of the second base.

Second base is extended more so that meas it will measure extended part plus the first base.

Second base = 7 + 5 = 12.

Now for the area.

A = 1/2(b1+b2)(h)
A = 1/2(7 + 12)(7)
A = 66.5

The area is 66.5 ft²

Hope this helps :)
calculista

Answer:

The area of the doghouse is [tex]66.5\ ft^{2}[/tex]

Step-by-step explanation:

we know that

The area of trapezoid is equal to

[tex]A=\frac{1}{2}(b1+b2)h[/tex]

where

b1,b2 are the parallel bases of trapezoid

h is the height of trapezoid

in this problem we have

[tex]b1=7\ ft[/tex]

[tex]b2=7+5=12\ ft[/tex]

[tex]h=7\ ft[/tex]

substitute

[tex]A=\frac{1}{2}(7+12)7=66.5\ ft^{2}[/tex]

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