Respuesta :

The  volume  of  the solution(in Ml)  needed  to  prepare 2.00 L  of 0.342 M  NaOH    is calculated using the below  formula

M1V1 =M2V2
M1=0.800 M
V1=?
M2=0.342  m
V2=  2.00  L

by  making  V1   the  subject  of the  formula = M2V2/M1

= 2.00 L x 0.342/ 0.800 =0.855  L  stock  solution  is neede