KOAL
contestada

Factor completely:
x^40–x^20
y^24+y^8
a^20–a^10+a^5
b^60+b^40–b^20

(^=to the power of)

Respuesta :

Cathenna
1) x^40–x^20 = x^20(x^20 - 1)

2) y^24+y^8 = y^8(y^16 + 1)

3) a^20–a^10+a^5 = a^5(a^15 - a^5 + 1)

4) b^60+b^40–b^20 = b^20(b^40 + b^20 - 1)

Hope this helps!

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