Respuesta :

We can use the following formula:

[tex]q=m\cdot c\cdot(T2-T1)[/tex]

Where:

q = heat = 1 kcal = 4184000J

c = specific heat (of silver) = 0.235 J °C /g

m = mass

T1 = Initial temperature = 10°C

T2 = Final temperature = 90°C

Therefore, solve for m:

[tex]\begin{gathered} m=\frac{q}{c(T2-T1)} \\ m=\frac{4184000}{0.235(90-10)} \\ m=222553.1915g \end{gathered}[/tex]

Answer:

222553.1915g